Question 9.2.1: Additional Answer Options

2022 - May/June - Paper 1 - Question 9

Or

Option 2

P_{\text{ave }}=V_{\text{ms }}I_{ms}

100=220\mathrm{I}_{\mathrm{rms}}

I_{\mathrm{rms}}=0,45\mathrm{~A}(0,455)

\mathrm{I}_{\mathrm{ms}}=\frac{\mathrm{V}_{\mathrm{ms}}}{\mathrm{R}} (1)

0,45=\frac{220}{R} (2)

R=488,89\Omega (3)

Or

Option 3

P_{\text{ave }}=V_{\text{ms }}I_{\text{ms }}

100=220\mathrm{I}_{\mathrm{ms}}

\mathrm{I}_{\mathrm{rms}}=0,45\mathrm{~A}(0,455)

P_{\text{ave }}=I_{\text{ms }}^2R (1)

100=(0,45)^2R (2)

R=493,83\Omega (3)

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Physical Sciences
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