Question 3.2.1: Additional Answer Options

2022 - November - Paper 1 - Question 3

Or

Option 2

B-C

Upwards as positive:

v_{\mathrm{f}}=\mathrm{v}_{\mathrm{i}}+\mathrm{a}\Delta\mathrm{t}

-12=0+(-9,8)\Delta t

\Delta t=1,22\mathrm{~s}

Or

Downwards as positive:

v_{f}=v_1+a\Delta t

12=0+(9.8)\Delta t

\Delta t=1,22\mathrm{~s}

Or

Option 3

A-C

Upwards as positive:

v_{\mathrm{f}}=\mathrm{v}_{\mathrm{i}}+\mathrm{a}\Delta\mathrm{t}

-12=12+(-9,8)\Delta t

\Delta t=2,45\mathrm{~s}

\Delta\mathrm{t}_{\mathrm{up}}=1,23\mathrm{~s}

Or

Downwards as positive:

v_{f}=v_{i}+a\Delta t

12=-12+(9,8)\Delta t

\Delta t=2,45\mathrm{~s}

\Delta t_{\mathrm{up}}=1,23\mathrm{~s}

Or

Option 4

A-C

Upwards as positive:

\Delta y=v\Delta t+1/2a\Delta t^2

0=(12)\Delta t+1/2(-9,8)\Delta t^2

\Delta t=2,45\mathrm{~s}

\Delta\mathrm{t}_{\mathrm{up}}=1,23\mathrm{~s}

Or

Downwards as positive:

\Delta y=v_1\Delta t+1/2a\Delta t^2

0=(-12)\Delta t+1/2(9,8)\Delta t^2

\Delta t=2,45\mathrm{~s}

\Delta t_{\mathrm{up}}=1,23\mathrm{~s}

Or

Option 5

A-B Or B-C

\left(E_{\text{mech }}\right)_{\text{Top }}=\left(E_{\text{mech }}\right)_{25m}

\left(E_{P}+E_{K}\right)_{Top}=\left(E_{P}+E_{K}\right)_{25m}

\left(\mathrm{mgh}+1/2\mathrm{mv}^2\right)_{Top}=\left(\mathrm{mgh}+1/2\mathrm{mv}^2\right)_{25\mathrm{~m}}

(9,8)h+0=0+(1/2)(12)^2

\Delta\mathrm{h}=7,35\mathrm{~m}

Upwards as positive:

\Delta\mathrm{y}=\left(\frac{\mathrm{v}_{\mathrm{i}}+\mathrm{v}_{\mathrm{f}}}{2}\right)\Delta\mathrm{t}

7,35=\left(\frac{12+0}{2}\right)\Delta t

\Delta\mathrm{t}=1,23\mathrm{~s}

Or

Downwards as positive:

\Delta\mathrm{y}=\left(\frac{\mathrm{v}_{\mathrm{i}}+\mathrm{v}_{\mathrm{f}}}{2}\right)\Delta\mathrm{t}

-7,35=\left(\frac{-12+0}{2}\right)\Delta t

\Delta\mathrm{t}=1,23\mathrm{~s}

Or

Option 6

A-B or B-C

W_{\mathrm{nc}}=\Delta\mathrm{K}+\Delta\mathrm{U}

W_{\mathrm{nc}}=\Delta\mathrm{K}+\mathrm{mg}\left(\mathrm{h}_{\mathrm{f}}-\mathrm{h}_{\mathrm{i}}\right)

0=1/2mv_{f}^2-1/2mv_{i}^2+mgh_{f}-mgh_{i}

0=1/2\left(0^2-12^2\right)+(9,8)\Delta h

\Delta\mathrm{h}=7,35\mathrm{~m}

Upwards as positive:

\Delta\mathrm{y}=\left(\frac{\mathrm{v}_{\mathrm{i}}+\mathrm{v}_{\mathrm{f}}}{2}\right)\Delta\mathrm{t}

7,35=\left(\frac{12+0}{2}\right)\Delta t

\Delta\mathrm{t}=1,23\mathrm{~s}

Or

Downwards as positive:

\Delta y=\left(\frac{v_{i}+v_{f}}{2}\right)\Delta t

-7,35=\left(\frac{-12+0}{2}\right)\Delta t

\Delta\mathrm{t}=1,23\mathrm{~s}

Or

Option 7

A-B or B-C

W_{\text{net }}=\Delta E_{k}

w\Delta y\cos\theta=1/2mv_{f}^2-1/2mv_{i}^2

(9,8)\Delta y\cos180^{\circ}=0-1/2(12)^2

\Delta\mathrm{y}=7,35\mathrm{~m}

Upwards as positive:

\Delta\mathrm{y}=\left(\frac{\mathrm{v}_{\mathrm{i}}+\mathrm{v}_{\mathrm{f}}}{2}\right)\Delta\mathrm{t}

7,35=\left(\frac{12+0}{2}\right)\Delta t

\Delta\mathrm{t}=1,23\mathrm{~s}

Or

Downwards as positive:

\Delta\vartheta=\left(\frac{v_{i}+v_{f}}{2}\right)\Delta t

-7,35=\left(\frac{-12+0}{2}\right)\Delta t

\Delta\mathrm{t}=1,23\mathrm{~s}

Or

Option 8

A-B

Upwards as positive:

v_{f}^2=v_{i}^2+2a\Delta y

0^2=12^2+2(-9,8)\Delta y

\Delta\mathrm{y}=7,35\mathrm{~m}

\Delta\mathrm{y}=\left(\frac{\mathrm{v}_{\mathrm{i}}+\mathrm{v}_{\mathrm{f}}}{2}\right)\Delta\mathrm{t}

7,35=\left(\frac{12+0}{2}\right)\Delta t

\Delta\mathrm{t}=1,23\mathrm{~s}

Or

Downwards as positive:

v_{f}^2=v_{i}^2+2a\Delta y

0^2=(-12)^2+2(9,8)\Delta y

\Delta y=-7,35\mathrm{~m}

\Delta y=\left(\frac{v_{\mathrm{i}}+\mathrm{v}_{\mathrm{f}}}{2}\right)\Delta\mathrm{t}

-7,35=\left(\frac{-12+0}{2}\right)\Delta t

\Delta\mathrm{t}=1,23\mathrm{~s}

Or

Option 9

B-C

Upwards as positive:

v_{f}^2=v_{i}^2+2a\Delta y

(-12)^2=0^2+2(-9,8)\Delta y

\Delta\mathrm{y}=-7,35\mathrm{~m}

\Delta\mathrm{y}=\left(\frac{\mathrm{v}_{\mathrm{i}}+\mathrm{v}_{\mathrm{f}}}{2}\right)\Delta\mathrm{t}

-7,35=\left(\frac{-12+0}{2}\right)\Delta t

\Delta\mathrm{t}=1,23\mathrm{~s}

Or

Downwards as positive:

v_{f}^2=v_{i}^2+2a\Delta y

(12)^2=0^2+2(9,8)\Delta y

\Delta\mathrm{y}=7,35\mathrm{~m}

\Delta\mathrm{y}=\left(\frac{\mathrm{v}_{\mathrm{i}}+\mathrm{v}_{\mathrm{f}}}{2}\right)\Delta\mathrm{t}

7,35=\left(\frac{12+0}{2}\right)\Delta t

\Delta t=1,23\mathrm{~s}

Or

Option 10

A-B

Upwards as positive:

\Delta\mathrm{y}=\left(\frac{\mathrm{v}_{\mathrm{i}}+\mathrm{v}_{\mathrm{f}}}{2}\right)\Delta\mathrm{t}

\Delta y=\left(\frac{12+0}{2}\right)\Delta t

\Delta y=6\Delta t

v_{f}^2=v_{i}^2+2a\Delta y

0=(12)^2+2(-9,8)(6\Delta t)

\Delta t=1,22\mathrm{~s}

Or

Downwards as positive:

\Delta\mathrm{y}=\left(\frac{\mathrm{v}_{\mathrm{i}}+\mathrm{v}_{\mathrm{f}}}{2}\right)\Delta\mathrm{t}

\Delta\mathrm{y}=\left(\frac{-12+0}{2}\right)\Delta t

\Delta y=-6\Delta t

v_{f}^2=v_{i}^2+2a\Delta y

0=(-12)^2+2(9,8)(-6\Delta t)

\Delta t=1,22s

Or

Option 11

B-C

Upwards as positive:

\Delta\mathrm{y}=\left(\frac{\mathrm{v}_{\mathrm{i}}+\mathrm{v}_{\mathrm{f}}}{2}\right)\Delta\mathrm{t}

\Delta\mathrm{y}=\left(\frac{0-12}{2}\right)\Delta\mathrm{t}

\Delta y=-6\Delta t

v_{f}^2=v_{i}^2+2a\Delta y

-12=(0)^2+2(-9,8)(-6\Delta t)

\Delta t=1,22\mathrm{~s}

Or

Downwards as positive:

\Delta y=\left(\frac{v_{i}+v_{f}}{2}\right)\Delta t

\Delta y=\left(\frac{12+0}{2}\right)\Delta t

\Delta y=6\Delta t

v_{f}^2=v_{i}^2+2a\Delta y

12^2=0^2+2(9,8)(6\Delta t)

\Delta\mathrm{t}=1,22\mathrm{~s}

Or

Option 11

A-B

Upwards as positive:

\left.\begin{array}{l}\mathrm{F}_{\text{net }}\Delta\mathrm{t}=\mathrm{m}\Delta\mathrm{v}\\ \mathrm{F}_{\text{net }}\Delta\mathrm{t}=\mathrm{m}\left(\mathrm{v}_{\mathrm{f}}-\mathrm{v}_{\mathrm{i}}\right)\end{array}\right\}\begin{aligned} & \text{Any one }\end{aligned}

-(9,8)\Delta t=0-12

\Delta\mathrm{t}=1,22\mathrm{~s}

Or

Downwards as positive:

\left.\begin{array}{l}\mathrm{F}_{\text{net }}\Delta\mathrm{t}=\mathrm{m}\Delta\mathrm{v}\\ \mathrm{F}_{\text{net }}\Delta\mathrm{t}=\mathrm{m}\left(\mathrm{v}_{\mathrm{f}}-\mathrm{v}_{\mathrm{i}}\right)\end{array}\right\}\begin{aligned} & \text{ Any one }\end{aligned}

(9,8)\Delta t=12-0

\Delta t=1,22\mathrm{~s}

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Grade 12 Physical Sciences
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