Question 5.2: Additional Answer Options

2022 - May/June - Paper 1 - Question 5

Or

Option 2

\left.\begin{array}{rl}P & =\frac{W}{\Delta t}\\ & =\frac{F\Delta x\cos\theta}{\Delta t}\text{ or }/of\frac{F\Delta y\cos\theta}{\Delta t}\\ & =\frac{mg\Delta x\cos0^{\circ}}{\Delta t}\end{array}\right\}Anyone

=\frac{(1250)(9,8)(5,8)\cos0^{\circ}}{60}

=1184,17\mathrm{W}\quad(1184,167)

Or

Option 3

\left.\begin{array}{rl}\mathrm{P} & =\frac{\mathrm{W}}{\Delta\mathrm{t}}\\ & =\frac{\mathrm{F}\Delta\mathrm{x}\cos\theta}{\Delta\mathrm{t}}\text{ or }\frac{\mathrm{F}\Delta\mathrm{y}\cos\theta}{\Delta\mathrm{t}}\\ & =\frac{\mathrm{mg\Delta x\operatorname{cos}180^{\circ}}}{\Delta\mathrm{t}}\end{array}\right\}Anyone

=\frac{(1250)(9,8)(5,8)\cos180^{\circ}}{60}

=-1184,17\mathrm{~W}\quad(-1184,167)

\text{ Power dissipated by the crane}=1184,17\mathrm{W}

Or

Option 4

\mathrm{P}_{\mathrm{ave}}=\mathrm{FV}_{\mathrm{ave}}

=1250(9,8)\frac{5,8}{60}

=1184,17\mathrm{~W}

Related subjects & topics
Grade 12 Physical Sciences
Explore similar posts in our community