Question 4.3: Additional Answer Options

2022 - May/June - Paper 1 - Question 4

Or

Option 2

Right as positive:

\left.\begin{array}{c}\Delta\mathrm{p}_{\text{toy cart}}=-\Delta\mathrm{p}_{\text{rocket}}\\ \mathrm{m}_1\left(\mathrm{v}_{1(\mathrm{f})}-\mathrm{v}_{1(\mathrm{i})}\right)=-\mathrm{m}_2\left(\mathrm{v}_{2(\mathrm{f})}-\mathrm{v}_{2(\mathrm{i})}\right)\end{array}\right\}Anyone

(20)(0.6-2.5)=-(m)(30-2,5)

m_2=1,38\mathrm{~kg}

Or

Left as positive:

\left.\begin{array}{rl}\Delta\mathrm{p}_{\text{toy cart}} & =-\Delta\mathrm{p}_{\text{rocket}}\\ \mathrm{m}_1\left(\mathrm{v}_{1(\mathrm{f})}-\mathrm{v}_{1(\mathrm{i})}\right) & =-\mathrm{m}_2\left(\mathrm{v}_{2(\mathrm{f})}-\mathrm{v}_{2(\mathrm{i})}\right)\end{array}\right\}Anyone

(20)[-0,6-(-2,5)]=-(\mathrm{m})](-30-(-2,5)]

\mathrm{m}_2=1,38\mathrm{~kg}

Related subjects & topics
Grade 12 Physical Sciences
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