Question 3.2.2: Additional Answer Options

2022 - May/June - Paper 1 - Question 3

Or

Option 2

Upwards as positive:

v_{f}^2=v_{i}^2+2a\Delta y (1)

0=(15)^2+(2)(-9,8)\Delta y (2)

\Delta\mathrm{v}=11.48\mathrm{~m}

\text{ Height }=11,48+30 (3)

=41,48\mathrm{~m} (4)


Or

Downwards as positive:

v_{f}^2=v_{i}^2+2a\Delta y (1)

0=(-15)^2+(2)(9,8)\Delta y (2)

\Delta y=-11,48m

\text{ Heiaht }=11.48+30 (3)

=41,48\mathrm{~m} (4)


Or

Option 3

Upwards as positive:

\Delta y=\left(\frac{v_{i}+v_{f}}{2}\right)\Delta t (1)

\Delta y=\left(\frac{15+0}{2}\right)(1,53) (2)

=11,48\mathrm{~m}

\text{ Height }=11,48+30 (3)

=41,48\mathrm{~m} (4)


Or

Downwards as positive:

\Delta y=\left(\frac{v_{i}+v_{f}}{2}\right)\Delta t (1)

\Delta y=\left(\frac{-15+0}{2}\right)(1,53) (2)

=-11,48\mathrm{~m}

\text{ Height }=11,48+30 (3)

=41,48\mathrm{~m} (4)


Or

Option 4

Upwards as positive:

v_{f}^2=v_{i}^2+2a\Delta y (1)

v_{f}^2=(-15)^2+(2)(-9,8)(-30) (2)

v_{f}=-28,51\mathrm{~m}\cdot\mathrm{s}^{-1}

v_{f}^2=v_{i}^2+2a\Delta y

(-28,51)^2=(0)^2+(2)(-9,8)\Delta y (3)

\Delta y=41,48m

\text{ Height }=41,48\mathrm{m} (4)


Or

Downwards as positive:

v_{f}^2=v_{i}^2+2a\Delta y (1)

v_{f}^2=(15)^2+(2)(9,8)(30) (2)

v_{f}=28,51\mathrm{~m}\cdot\mathrm{s}^{-1}

v_{f}^2=v_{i}^2+2a\Delta y

(28,51)^2=(0)^2+(2)(9,8)\Delta y (3)

\Delta y=41,48m

\text{ Height }=41,48\mathrm{m} (4)


Or

Option 5

\left.\begin{array}{l}W_{\text{net }}=\Delta E_{k}\\ w\Delta x\cos180^{\circ}=1/2m\left(v_{f}^2-v_{i}^2\right)\end{array}\right\}Anyone (1)

(9,8)(\Delta x)\cos180^{\circ}=1/2\left(0-15^2\right) (2 + 3)

\Delta x=11,47\mathrm{~m}

\text{ Height above the ground}={30}+11,47=41,48\mathrm{m} (4)


Or

Option 6

\left.\begin{array}{l}\left(E_{\text{mech }}\right)_{\text{Top }}=\left(E_{\text{mech }}\right)_{30}m\\ \left(E_{P}+E_{K}\right)_{\text{Top }}=\left(E_{P}+E_{K}\right)_{30m}\\ \left(mgh+1/2mv^2\right)_{Top}=\left(mgh+1/2m^2\right)_{30m}\end{array}\right\}Anyone (1)

(9,8)h+0=(9,8)(30)+(1/2)(15)^2 (2 + 3)

\mathrm{h}=41,48\mathrm{~m} (4)


Or

Option 7

\left.\begin{array}{l}W_{nc}=\Delta E_{p}+\Delta E_{k}\\ 0=mg\left(h_{f}-h_{i}\right)+1/2m\left(v_{f}^2-v_{i}^2\right)\end{array}\right\}Anyone (1)

0=(9,8)\left(h_{f}-0\right)+1/2\left(0-15^2\right) (2 + 3)

\mathrm{h}=11,47\mathrm{~m}

\text{ Height above the ground }=30+11,47=41,48\mathrm{m} (4)

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