Question 6.4: Additional Answer Options

2021 - November - Paper 1 - Question 6

Or

Option 2

f_{L}=\frac{v\pm v_{L}}{v\pm v_{s}}f_{s}\text{ OR }f_{L}=\frac{v}{v-v_{s}}f_{s}

\frac{v}{\lambda_{L}}=\left(\frac{v+0}{v-v_{s}}\right)f_{s}

\frac{340}{0,5-0,05}=\left(\left(\frac{340+0}{340-v_{s}}\right)\right)680

\frac{340}{0,45}=\left(\frac{340+0}{340-v_{s}}\right)680

v_{s}=34m\cdot s^{-1}\quad(33,67-34,04)

Or

Option 3

f_{L}=\frac{v\pm v_{L}}{v\pm v_{s}}f_{s}\text{ OR }f_{L}=\frac{v}{v-v_{s}}f_{s}

\frac{v}{\lambda_{L}}=\left(\frac{v+0}{v-v_{s}}\right)\frac{v}{\lambda_{s}}

\therefore\quad\frac{1}{\lambda_{\mathrm{L}}}=\left(\frac{\mathrm{v}+0}{\mathrm{v}-\mathrm{v}_{\mathrm{s}}}\right)\frac{1}{\lambda_{\mathrm{s}}}

\left.\frac{1}{0,5-0,05}=\left(\frac{340+0}{340-v}\right)\right.{1}{0,5}

\frac{1}{0,45}=\left(\frac{340+0}{340-v_{s}}\right)\frac{1}{0,5}

v_{s}=34m\cdot s^{-1}\quad(33,67-34,04)

Or

Option 4

f_{L}=\frac{v\pm v_{L}}{v\pm v_{s}}f_{s}\text{ OR }f_{L}=\frac{v}{v-v_{s}}f_{s}

v_1=v_2

\mathrm{f}_{\mathrm{S}}\lambda_1=\mathrm{f}_{\mathrm{L}}\lambda_2

(600)(0.5)=f_1(0.45)

f_{L}=755,56\mathrm{~Hz}

755,56=\left(\frac{340+0}{340-v_{s}}\right)680

v_{s}=34m\cdot s^{-1}\quad(33,67-34,04)

Related subjects & topics
Grade 12 Physical Sciences
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