Additional Answer Options: 3.3.1

3.1

10 m∙s^-1.  

1 mark

3.2

The gradient represents the acceleration due to gravity (g) which is constant for free fall.  

1 mark

3.3.1

Option 1:

Upwards as positive:

\Delta y=v_i \Delta t+1 / 2 a \Delta t^2  

=(10)(2)+1 / 2(9,8)\left(2^2\right)  

=39,6 \mathrm{~m} 

\text{ Height }=39,6\mathrm{m}  

OR

Downwards as positive:

\Delta \mathrm{y}=\mathrm{v}_{\mathrm{i}} \Delta \mathrm{t}+1 / 2 \mathrm{a} \Delta \mathrm{t}^2  

=(-10)(2)+1 / 2(-9,8)\left(2^2\right)  

=-39,6 \mathrm{~m} 

\text{ Height }=39.6\mathrm{m}   

There are more ways to answer this question. To view other options, click here.

3 marks

(3 x 1 mark)

3.3.2

Option 1:

\mathrm{v}_{\mathrm{f}}=\mathrm{v}_{\mathrm{i}}+\mathrm{a} \Delta \mathrm{t}  

0=-25+(9,8)(\Delta t)  

\Delta \mathrm{t}=2,55 \mathrm{~s} 

\text{ Total time T }=8+2,55  

=10,55 \mathrm{~s}  

There are more ways to answer this question. To view other options, click here.

4 marks

(4 x 1 mark)

3.4.1

0,2s.  

1 mark

3.4.2

1 mark

3.4.3

-27 (m.s^-1).  

1 mark

3.5

Inelastic. 

The speeds at which it strikes and leaves the ground are not the same / The kinetic energies will not be the same.  

2 marks

(2 x 1 mark)