Additional Answer Options: 8.2.2

2023 - May/June - Paper 1 - Question 8

No memo is currently available

Or

Option 2

Part 1

\frac{1}{R_{p}}=\frac{1}{R_1}+\frac{1}{R_2}

\frac{1}{R_{p}}=\frac17+\frac13

R_{p}=2,1\Omega

Or

R_{p}=\frac{R_1R_2}{R_1+R_2}

R_{p}=\frac{(7)(3)}{7+3}

=2,1\Omega

Part 2

R=\frac{V}{I_{T}}

2.1=\frac{10,5}{l_{T}}

\mathrm{I}_{\mathrm{T}}=5\mathrm{~A}

Or

Option 3

I_{3\Omega}=\frac73\times1,5

=3,5\mathrm{~A}

I_{\text{total }}=3,5+1,5

=5\mathrm{~A}

Or

Option 4

I_{S}=\left(\frac{R_{3\Omega}}{R_{3\Omega}+R_{S}}\right)\times I_{\text{total }}

1,5=\frac{3}{3+7}\times I_{\text{total }}

I_{\text{total }}=5\mathrm{~A}

Related subjects & topics
Physical Sciences
Explore similar posts in our community