5.1
|
A force is non-conservative if the work it does/done on an object which is moving between two points depends on the path taken.
Or
A force is non-conservative if the work it does/done in moving an object around a closed path is non-zero.
Tip: a non-conservative force does not change the mechanical energy of a system.
|
2 marks
(1 x 2 marks)
|
5.2
|
Option 1
Any one (1)
(2 + 3 + 4)
(5)
Tips:
- The crate starts from rest and accelerates up the slope.
- It helps to draw a free-body diagram to show all of the forces acting on an object in order to identify which of the forces do the work.
- In this case, negative work is done against gravity and friction. Positive work is done by the tension in the rope. Using the formula W = FΔxcosθ, calculate the work done by each of the forces acting on the crate.
- The work done by the frictional force is equal to Wf = (13,5)(15,6)cos 180°
- The work done against gravity is equal to Wg = (20)(9,8)(15,6sin18°)cos180°
- The work done by the tension is equal to WT = (96,8)(15,6)cos0°
- The normal force does no work since the normal force acts perpendicularly to the direction of the displacement.
- Using the work-energy theorem Wnet = ΔEk
There are more ways to answer this question. To view other options, click here.
|
5 marks
(5 x 1 mark)
Marking criteria:
- (1) Any one of the correct equation
- (2) Correct substitution for work done by gravity or ΔEp
- (3) Correct substitution for work done by motor and friction
- (4) Correct substitution for ∆Ek
- (5) Correct final answer: 5,96 m·s-1
|
5.3
|
Option 1
(1)
(2)
(3)
Tips:
- The average power is the product of the applied force of the motor and the average velocity of the crate.
- Since the crate accelerates uniformly from rest to a speed of 5,96 m·s-1, the average speed is the average of these two velocities.
There are more ways to answer this question. To view other options, click here.
|
3 marks
(3 x 1 mark)
Marking criteria:
- (1) Correct equation for power
- (2) Correct substitution into power equation
- (3) Correct final answer: 288,46 W
- Range: 286,46 W to 288,73 W
|
5.4
|
Tips:
- Although older papers may indicate that you may also use components in free-body diagrams, they will no longer be marked be awarded the marks.
- Do not resolve the weight into parallel and perpendicular components in any free-body diagram.
N |
FN/196N/normal/Fnormal |
f |
(kinetic) friction/Ff/Fw/fk |
w |
Fg/Fw/weight/mg/gravitational force/FEarth on crate |
|
3 marks
(3 x 1 mark)
|
5.5
|
How to approach this question:
- If upwards is taken as the positive direction:
- When the rope breaks, the crate continues to move up the slope but slows down until it comes to rest at point D. Then, it slides down the slope with a less steep gradient because friction and gravity act in opposite directions.
Or
- If upwards is considered as negative:
|
4 marks
(4 x 1 mark)
Marking criteria:
- The first straight line starts at zero with a positive gradient, reaching a maximum
velocity.
- A second straight line with the negative gradient from maximum velocity to zero.
- The third straight line continues from the second line at zero and extends below the x-axis.
- The third line has a smaller negative gradient than the second line.
|