Question 8.2.2: Additional Answer Options

2022 - May/June - Paper 1 - Question 8

Or

Option 2

\varepsilon=I(R+r)

=0,8((4+8))+0,8\times0,5

=10\mathrm{~V}


Or

Option 3

V_8=IR

=(0,8)(8)

=6,4\mathrm{~V}

V_{\text{ext }}=3.2+6.4

=9,6\mathrm{~V}

V_{\text{int }}=\mathrm{Ir}

=(0,8)(0,5)

=0,4\mathrm{~V}

\left.\begin{array}{rl}\varepsilon & =I(R+r)\\  & =V_{\text{ext }}+V_{\text{int }}\end{array}\right\}Any one

=9,6+0,4

=10\mathrm{~V}

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