Question 2.3: Additional Answer Options

2021 - May/June - Paper 1 - Question 2

Or

Option 2

2 kg block:

\left.\begin{array}{l}\mathrm{F}_{\mathrm{net}}=\mathrm{ma}\\ \mathrm{F}_{\mathrm{net}}=0\\ \mathrm{T}-\mathrm{w}=0\end{array}\right\}Anyone

\mathrm{T}=\mathrm{w}=\mathrm{mq}=(2)(9,8)

\mathrm{T}=19,6\mathrm{~N}

Or

Option 3

W_{\text{net }}=\Delta E_{k}

W_{W}+W_{N}+W_{F}+W_{f}+W_{T}=0

0+0+F\Delta x\cos\theta+f\Delta x\cos\theta+T\Delta x\cos\theta=0

(29,6)\cos0^{\circ}+(10)\cos180^{\circ}+\mathrm{T}\cos180^{\circ}=0

29,6-10-T=0

\mathrm{T}=19,6\mathrm{~N}

Or

Option 4

\mathrm{W}_{\mathrm{nc}}=\Delta\mathrm{E}_{\mathrm{p}}+\Delta\mathrm{E}_{\mathrm{k}}

W_{F}+W_{f}+W_{T}=0+0

\mathrm{F}\Delta\mathrm{x}\cos\theta+\mathrm{f}\Delta\mathrm{x}\cos\theta+\mathrm{T}\Delta\mathrm{x}\cos\theta=0

(29,6)\cos0^{\circ}+(10)\cos180^{\circ}+\mathrm{T}\cos180^{\circ}=0

29,6-10-T=0

\mathrm{T}=19,6\mathrm{~N}

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Physical Sciences
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