2.1.1
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![](https://studyclixsazalive.blob.core.windows.net/cms/media/52gncy1k/za-phys-memo-2019-may-june-paper-1-q2.jpg?rmode=max&width=287&height=268)
F![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg) |
FA / 90N / F90 |
w![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg) |
Fg / Fw / weight/mg / Gravitational force |
f![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg) |
(Kinetic) Friction / Ff / / fk |
N![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg) |
FNormal / Normal / FN |
Tips:
- As of 2024 no marks will be awarded for free-body diagrams if the weight has been resolved into two components.
- Since the question is out of four marks, it indicates that four forces are acting on the lawn mower.
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4 marks
(4 x 1 mark)
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2.1.2
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It is moving at constant speed in a straight line, the acceleration is zero/ the net force (resultant) acting on it is zero/it is moving at constant velocity. ![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
Tips:
- When an object is in equilibrium, there is no resultant force acting on the system so the object moves at a constant velocity or remains at rest.
- In this case, the person is pushing the lawnmower at a constant speed so it must be in equilibrium.
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1 mark
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2.1.3
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Option 1
Any one (1)![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
(2)![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
(3)![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
Or
Option 2
Any one (1)![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
(2)![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
(3)![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
Or
Option 3
Any one (1) ![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
(2) ![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
(3)![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
Tip: the horizontal component of the applied force must be equal to the friction for the lawnmower to move at a constant speed.
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3 marks
(3 x 1 mark)
Marking criteria:
- (1) Formula
![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
- (2) Substitution
![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
- (3) Answer
![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
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2.1.4
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How to approach this question:
- You need to calculate the acceleration using the given information.
Option 1
Part 1:
![v_{f}=v_{i}+a\Delta t](https://studyclixsazalive.blob.core.windows.net/cms/media/462cae6e-08e1-4ce0-8bef-cfa940a9e791.svg)
![2=0+a(3)](https://studyclixsazalive.blob.core.windows.net/cms/media/7eefd3e0-6b82-4105-b455-ef57f138bf45.svg) ![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg) ![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
![\mathrm{a}=0,67\mathrm{~m}\cdot\mathrm{s}^{-2}](https://studyclixsazalive.blob.core.windows.net/cms/media/2e9ea732-fddd-4568-a9e2-0be4d5eb7969.svg)
Part 2:
- Use Newton's second law to calculate the force.
![\mathrm{F}_{\text{net }}=\mathrm{ma}](https://studyclixsazalive.blob.core.windows.net/cms/media/9963f2ee-6632-4ed9-9757-1f48c7e2d2e4.svg) ![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
![F\cos40^{\circ}-68,94=15(0,67)](https://studyclixsazalive.blob.core.windows.net/cms/media/178a9224-d744-4238-9ce2-fe9d03a83363.svg) ![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg) ![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
![\mathrm{F}=103,11\mathrm{N}(103,05\mathrm{N}-103,11\mathrm{N})](https://studyclixsazalive.blob.core.windows.net/cms/media/018be200-661d-4b86-b8d8-ac84dcc26119.svg) ![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
- Remember, you are asked for the force and not just the horizontal component of the force.
Or
![F_{net}=ma](https://studyclixsazalive.blob.core.windows.net/cms/media/7e0bae60-6ba1-43b2-ae8f-3086f0c2e137.svg) ![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
![\mathrm{F}\cos320^{\circ}-f=15(0,67)](https://studyclixsazalive.blob.core.windows.net/cms/media/a6faa803-535f-4c57-bb70-6865de2fab79.svg)
![F\cos320^{\circ}-68,94=15(0,67)](https://studyclixsazalive.blob.core.windows.net/cms/media/516b0701-a96c-4118-88c4-c67122fda836.svg) ![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg) ![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
![\mathrm{F}=103,11\mathrm{~N}](https://studyclixsazalive.blob.core.windows.net/cms/media/bb0f6f52-0ea5-4085-8c73-10f89f8beda8.svg) ![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
There are more ways to answer this question. To view other options, click here.
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6 marks
(6 x 1 mark)
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2.2
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Option 1
![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg) ![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
Or
Option 2
![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
![\mathrm{g}=2\mathrm{~m}\cdot\mathrm{s}^{-2}](https://studyclixsazalive.blob.core.windows.net/cms/media/0099d9a8-09a0-45a2-af17-e6e438182733.svg)
![\mathrm{g}=\frac{\mathrm{GM}}{\mathrm{R}^2}](https://studyclixsazalive.blob.core.windows.net/cms/media/9fe462f7-6ab4-4ed8-adf2-967b866ab133.svg)
![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
![M=1,08\times10^{22}\mathrm{~kg}](https://studyclixsazalive.blob.core.windows.net/cms/media/a53e34b1-db34-484e-80c0-dabb50dc43e7.svg) ![check](https://studyclixsazalive.blob.core.windows.net/cms/media/binl1ryy/tick-green-circle.svg)
Tip: the universal gravitational constant, G, is given on the formula sheet.
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4 marks
(4 x 1 mark)
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